x^2-5(x-4)+12x-8=

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Solution for x^2-5(x-4)+12x-8= equation:


Simplifying
x2 + -5(x + -4) + 12x + -8 = 0

Reorder the terms:
x2 + -5(-4 + x) + 12x + -8 = 0
x2 + (-4 * -5 + x * -5) + 12x + -8 = 0
x2 + (20 + -5x) + 12x + -8 = 0

Reorder the terms:
20 + -8 + -5x + 12x + x2 = 0

Combine like terms: 20 + -8 = 12
12 + -5x + 12x + x2 = 0

Combine like terms: -5x + 12x = 7x
12 + 7x + x2 = 0

Solving
12 + 7x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + x)(3 + x) = 0

Subproblem 1

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(3 + x)' equal to zero and attempt to solve: Simplifying 3 + x = 0 Solving 3 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + x = 0 + -3 x = 0 + -3 Combine like terms: 0 + -3 = -3 x = -3 Simplifying x = -3

Solution

x = {-4, -3}

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